- C++
B2064斐波那契数列题解(define版)
- 2024-12-14 15:45:19 @
#include <stdio.h>
#include <math.h>
#define _ printf("%.0f\n",((pow((1 + sqrt(5)) / 2,r)) - (pow((1 - sqrt(5)) / 2,r))) / sqrt(5));
#define __ main()
#define ___ {
#define ____ }
#define _____ a
#define ______ ;
#define _______ scanf("%d",&a)
#define ________ for(int i = 0; i < a; i = -(~i))
#define _________ r
#define __________ scanf("%d",&r);
#define ___________ int
#define ____________ return 0
___________ __ ___
___________ _____ ______
_______ ______
________ ___
___________ _________ ______
__________ ______
_ ______
____
____________ ______
____
1 comments
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松饼好吃 LV 5 @ 2024-12-14 19:54:28
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